22y^2+71y-21=0

Solution for 22y^2+71y-21=0 equation:

22y^2+71y-21=0

a = 22; b = 71; c = -21;
Δ = b2-4ac
Δ = 712-4·22·(-21)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-83}{2*22}=\frac{-154}{44}
=-3+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+83}{2*22}=\frac{12}{44}
=3/11
$